# Construct-the-Rectangle

Jan 24, 2018

For a web developer, it is very important to know how to design a web page’s size. So, given a specific rectangular web page’s area, your job by now is to design a rectangular web page, whose length L and width W satisfy the following requirements:

1. The area of the rectangular web page you designed must equal to the given target area.

2. The width W should not be larger than the length L, which means L >= W.

3. The difference between length L and width W should be as small as possible. You need to output the length L and the width W of the web page you designed in sequence. Example: Input: 4 Output: [2, 2] Explanation: The target area is 4, and all the possible ways to construct it are [1,4], [2,2], [4,1]. But according to requirement 2, [1,4] is illegal; according to requirement 3, [4,1] is not optimal compared to [2,2]. So the length L is 2, and the width W is 2. Note: The given area won’t exceed 10,000,000 and is a positive integer The web page’s width and length you designed must be positive integers.

1. L, W is int
2. L*W=Area
3. L >= W > 0
4. min |L-W|

vector<int> constructRectangle(int area) {
int L, W;
int sqrt_a = sqrt(area);
W = L = sqrt_a;
int a = W*L;
while(a != area) {
if (a < area) L++;
else if (a > area) W--;
a = W*L;
}
return {L, W};
}


public int[] constructRectangle(int area) {
int w = (int)Math.sqrt(area);
while (area%w!=0) w--;
return new int[]{area/w, w};
}

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